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Mathematics 17 Online
OpenStudy (anonymous):

check please FOIL

OpenStudy (anonymous):

x(x-3) = (x+2)^2

OpenStudy (anonymous):

x * x = x x * 2 = 2x

OpenStudy (anonymous):

is that right so far?

OpenStudy (noseboy908):

x*x does not equal x.

OpenStudy (noseboy908):

rethink it

OpenStudy (anonymous):

2x

OpenStudy (noseboy908):

no, that'd be x+x. for your future knowledge, x*x= x^2

OpenStudy (anonymous):

oh, okay so x * x = x^2 x * 2 = 2x ????

OpenStudy (jdoe0001):

\(\bf x(x-3) = (x+2)^2\implies (x\cdot x)+(x\cdot -3)=(x+2)(x+2)\)

OpenStudy (noseboy908):

yeah, that's one side of it

OpenStudy (noseboy908):

aptly stated jdoe

OpenStudy (jdoe0001):

\(\bf (x+2)(x+2)\implies (x\cdot x)+(x\cdot 2)+(2\cdot x)+(2\cdot 2)\)

OpenStudy (anonymous):

x^2 + -3x =

OpenStudy (anonymous):

wtf im so lost now

OpenStudy (anonymous):

>,<

OpenStudy (jdoe0001):

\(\Large \begin{array}{cccl} x(x-3) &= &(x+2)^2\\ (x\cdot x)+(x\cdot -3)& = & (x\cdot x)+(x\cdot 2)+(2\cdot x)+(2\cdot 2) \end{array}\)

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