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here is the problem
plug 7 into the second equation
I can try and help
\[f^{-1}(x) =\frac{ x-1 }{ 3 }\]let x=7: \[f^{-1}(x) =\frac{ 7-1 }{ 3 }=\frac{ 6 }{ 3 }\]
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i am sorry i was away 6/3 is not one of the options
but 6/3 = 2
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