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Solve the quadratic equation x2 - 4x + 57 = -5 by completing the square.
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\[x ^{2}-4x+57=-5\]
\[x ^{2}-4x=-62\]
\[(\frac{ -4 }{2 })^{2}=4\]
\[x ^{2}-4x+4=-58\]
\[\sqrt{x ^{2}}+\sqrt{4}=\sqrt{-58}\]
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@Mertsj
Im stuck here
\[A.x=1\pm i \sqrt{50}\]
\[B.x=2\pm \sqrt{58}\]
\[C.x=2\pm i \sqrt{58}\]
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\[D.x=2\pm \sqrt{62}\]
yeah you really are stuck
\[x ^{2}-4x=-62\] \[(x-2)^2=-62+4=-58\] \[x-2=\pm\sqrt{52}i\] \[x=2\pm\sqrt{58}i\]
Wow Thanks lol fan testimonial was only way of pming you Thanks alot
yw method i hope is more clear
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