Question

Algebra 2 help?? :/

Answer 1

How can \[2x ^{2}=x ^{2}+4x+8\] be set up as a system of equations?

Answer 2

A. \[y=x ^{2}-4\]
\[y=x^2+2x+8\]

Answer 3

B. \[y=x^2\]
\[y=x^2+4x+8\]

Answer 4

C.\[y=2x^2\]
\[y=x^2+4x+8\]

Answer 5

For the A :
we have :
2x^2-x^2-4x-8=0
K ?

Answer 6

D. \[y=x^2\]
\[y=2x+8\]

Answer 7

... okay..

Answer 8

Then you should be use from Quadratic equation formula caz you have this :)
Do you know that ?:)

Answer 9

No. I have no idea what I'm doing. I've been working on this for over an hour

Answer 10

All of your questions answer way is from Quadratic equation formula !:)

Answer 11

:/

Answer 12

Look its Quadratic equation form :
ax^2+bx-c=0
K ?!

Answer 13

Okay

Answer 14

@John_ES :)

Answer 15

Then to find x we use it :
ِِDelta =-4ac
X1=-b-\[X1=-b-\sqrt{\Delta}/2a\]
Got it ?:)

Answer 16

In the Quadratic equation we have 2 answers :X1 and X2 .

Answer 17

@TrixieDiVine