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OpenStudy (anonymous):

Algebra 2 help?? :/

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OpenStudy (anonymous):

How can \[2x ^{2}=x ^{2}+4x+8\] be set up as a system of equations?

OpenStudy (anonymous):

A. \[y=x ^{2}-4\] \[y=x^2+2x+8\]

OpenStudy (anonymous):

B. \[y=x^2\] \[y=x^2+4x+8\]

OpenStudy (anonymous):

C.\[y=2x^2\] \[y=x^2+4x+8\]

OpenStudy (anonymous):

For the A : we have : 2x^2-x^2-4x-8=0 K ?

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OpenStudy (anonymous):

D. \[y=x^2\] \[y=2x+8\]

OpenStudy (anonymous):

... okay..

OpenStudy (anonymous):

Then you should be use from Quadratic equation formula caz you have this :) Do you know that ?:)

OpenStudy (anonymous):

No. I have no idea what I'm doing. I've been working on this for over an hour

OpenStudy (anonymous):

All of your questions answer way is from Quadratic equation formula !:)

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OpenStudy (anonymous):

:/

OpenStudy (anonymous):

Look its Quadratic equation form : ax^2+bx-c=0 K ?!

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

@John_ES :)

OpenStudy (anonymous):

Then to find x we use it : ِِDelta =-4ac X1=-b-\[X1=-b-\sqrt{\Delta}/2a\] Got it ?:)

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OpenStudy (anonymous):

In the Quadratic equation we have 2 answers :X1 and X2 .

OpenStudy (anonymous):

@TrixieDiVine

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