Mathematics OpenStudy (anonymous):

Algebra 2 help?? :/ OpenStudy (anonymous):

How can $2x ^{2}=x ^{2}+4x+8$ be set up as a system of equations? OpenStudy (anonymous):

A. $y=x ^{2}-4$ $y=x^2+2x+8$ OpenStudy (anonymous):

B. $y=x^2$ $y=x^2+4x+8$ OpenStudy (anonymous):

C.$y=2x^2$ $y=x^2+4x+8$ OpenStudy (anonymous):

For the A : we have : 2x^2-x^2-4x-8=0 K ? OpenStudy (anonymous):

D. $y=x^2$ $y=2x+8$ OpenStudy (anonymous):

... okay.. OpenStudy (anonymous):

Then you should be use from Quadratic equation formula caz you have this :) Do you know that ?:) OpenStudy (anonymous):

No. I have no idea what I'm doing. I've been working on this for over an hour OpenStudy (anonymous): OpenStudy (anonymous):

:/ OpenStudy (anonymous):

Look its Quadratic equation form : ax^2+bx-c=0 K ?! OpenStudy (anonymous):

Okay OpenStudy (anonymous):

@John_ES :) OpenStudy (anonymous):

Then to find x we use it : ِِDelta =-4ac X1=-b-$X1=-b-\sqrt{\Delta}/2a$ Got it ?:) OpenStudy (anonymous):

In the Quadratic equation we have 2 answers :X1 and X2 . OpenStudy (anonymous):

@TrixieDiVine

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