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Calculus1
OpenStudy (anonymous):

How do you find the partial derivatives of f( x,y ) = ln( x+Sqt( x^2+y^2 ))

OpenStudy (anonymous):

use the chain rule, let u = x+ sqrt(x^2 +y^2), to get partial with respect to x, you may have to trig sub for wrt y

OpenStudy (anonymous):

Ok so I got 1/sqrt(x^2 + y^2). Is that the partial for x? or is there more to it?

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