Does anyone know how to find the GCF when turning a trinomial into a binomial pair?
For example the problem
2x^2 + 2x - 12 =
2(x^2 + x - 6)
Then I do the 2 by 2 punnet square chart and I put the x^2 in the first box and the -6 in the last box but how do I figure out what goes in the other 2 boxes I know its the 2 factors of the A & C and then I keep the sign of the middle term but how do I get it?

Question

Does anyone know how to find the GCF when turning a trinomial into a binomial pair?
For example the problem 
2x^2 + 2x - 12 = 
2(x^2 + x - 6)
Then I do the 2 by 2 punnet square chart and I put the x^2 in the first box and the -6 in the last box but how do I figure out what goes in the other 2 boxes I know its the 2 factors of the A & C and then I keep the sign of the middle term but how do I get it?

anonymous · Answer

so a = 1 and c = -6
their product is ac = (1)(-6) = -6
b = 1
so find factor of -6 that sum to 1.

that is s*t = -6
and s + t = 1

leozap1 · Answer

Would it be 3 * - 2

anonymous · Answer

you got it!  great job!

leozap1 · Answer

Ok but how do I find the GCF of these?|dw:1380729807430:dw|