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Algebra
OpenStudy (anonymous):

simplify the expression (4x^2y^3)^3

OpenStudy (anonymous):

\[(4x^2y^3)^3=(4x^2y^3)*(4x^2y^3)*(4x^2y^3)\]Taking the first two,\[(4x^2y^3)*(4x^2y^3)=16x^44x^2y^3*4x^2y^3y^6\]Factorizing,\[(4x^2y^3)*(4x^2y^3)=4x^2y^3(16x^4y^6)\]Therefore,\[(4x^2y^3)*(4x^2y^3)*(4x^2y^3)=(4x^2y^3)*(4x^2y^3)(16x^4y^6)\]This way,\[(4x^2y^3)^3=(4x^2y^3)(16x^4y^6)(16x^4y^6)\]Which is the same as,\[(4x^2y^3)^3=(4x^2y^3)(16x^4y^6)^2\]Which you should know, is a notable product.

OpenStudy (anonymous):

\[(xy)^3=xy(x^2y^2)^2\]

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