Question

i need to find the antiderivative of 2x+5/sqareroot of x^2+5x+7 and im really stuck

Answer 1

u substitution.

klet u = x^2 + 5x + 7 then du = (2x + 5)dx

Answer 2

so it would be u\u^1/2? and then i derive from there?

Answer 3

i think i got it thanks

Answer 4

no it would be du/u^1.2 or u^(-1/2)du. integrate from there.