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\(\large y = f(x) = 2x^2\)
put x = 0 u wud get, y = 0 that means, graph goes thru origin
so, answer must be graph1 or graph4
good question :) since its getting multiplied wid 2, it must better be narrow cuz it gets steeper
Okay, so since it is narrow because of steepness, it should be graph 1 correct?
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\(\huge \color{red}{\checkmark}\)
np :) okay !
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