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vertex form of quadratic :- \(\large a(x-h)^2 + k\) vertex : \(\large (h, k )\) axis of symmetry : \(\large x = h\)
compare the given equation wid the one above. can u ? :)
nope, just we need to compare given equaiton wid one above
\(\large y=3(x+2)^2-3 \) \(\large y=3(x--2)^2-3 \)
compare it wid vertex form of equation above, \(\large h = -2\) \(\large k = -3\)
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so, vertex : \(\large (-2, -3)\) axis of symmetry : \(\large x = -2\)
np :) glad it made some sense :))
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