Question

Help....

A man has two more nickels than dimes. He has $1.15 in all. How many coins of each kind does he have?

Which equation can be used to solve the problem?

Answer 1

Let n = number of nickels
d = number of dimes

n = 2 + d (equation 1)

.05n + .10d = 1.15 (equation 2)

Substitute equation 1 into equation 2:
.05(2 + d) + .10d = 1.15

.10 + .05d + .10d = 1.15

.10 + .15d = 1.15

.15d = 1.05

d = 7

n = 2 + d

n = 2 + 7

n = 9

The man has 9 nickels and 7 dimes

Answer 2

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