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Mathematics
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Suppose a triangle has two sides of the length of 3 and 4 and that the angle between the two sides is pi over 3. What is the length of the third side of the triangle?
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have you covered the Law of Cosines yet?
|dw:1380753556898:dw| \(\bf \textit{Law of Cosines} = c^2 = a^2+b^2-(2ab)cos(\measuredangle C)\\ \quad \\ \implies c = \sqrt{a^2+b^2-(2ab)cos(\measuredangle C)}\)
yeah, im doing the law of cosines now. I just wasn't sure how to set It up. thank you!
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