Question

if you have the function of f(x)=4cos(kt)+15 and the period if 1/60, what would k equal?

Answer 1

ignoring the constant (+15) which simply raises the graph 15 units, the wave is in the form:\[f(x) = Acos( \omega t)\]
w [omega] is the angular frequency. T is period.\[T = \frac{ 2 \pi }{ \omega }\]
\[k = \omega = \frac{ 2\pi }{ T } = \frac{ 2\pi }{ \frac{ 1 }{ 60 } } = 120\pi\]

Answer 2

Thank you! @Euler271

Answer 3

glad i could help :)