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Use the quadratic formula to find the roots of the equation. Round to tenths place if necessary. 11x^2 - x - 3 = 0 A. {-1, 1.2} B. {-11, 13.2} C. {-0.5, 0.6} D. no real solution
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x=(-b+sqrt(b^2-4ac))/(2a)
and x=(-b-sqrt(b^2-4ac))/(2a)
b=-1, a=11, c=-3 so x=(-(-1)+sqrt((-1)^2-4(11)(-3))/(2(11))=.56 x=(-(-1)-sqrt((-1)^2-4(11)(-3))/(2(11))=-.47
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Yes.
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oh ok its c they rounded the answers
so the answers is C .6 and -.5
are you french?
do you like my daft punk pic?
Haha no I am I am a quarter native american a quarter caucasian and half mexican.
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oh wow, you are very diverse, I am just a brown person haha.
your name sounded french to me lol
That is cool and thanks. :p
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