Question

Find three consecutive integers such that the sum of the first two is 24 more than the third

Answer 1

Let x be the first integer
(x + 1) the second
(x + 2) the third

the sum of the first two: x + (x + 1)

24 more than the third: (x + 2) + 24
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sum of the first two is 24 more than the third

x + (x + 1) = (x + 2) + 24 --> Solve this equation for x @Rreyes91