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Approximate Δ y using differentials for y = x2 – 4x at x = 6 when Δ x= dx = 0.03. Okay, what does Δ mean?
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The greek letter "delta", in mathematics and many sciences, it is used to express a change in a variable. In this case, the change in y, and the change in x.
so does it mean the change in x when or change in y when you take the differential?
does it want me to plug 6 into the un-differentiated problem and then again in the derivatives?
\[ \Delta y\approx dy=y'dx \]
In this case \(\Delta x=dx\)
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ah okay. thats given so its just derivative multiplied by that given value
\(dy\) is a linear approximation in the change of \(y\).
Whereas \(\Delta y\) is the exact change of \(y\).
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