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given that 2016k is a perfect square, what is the smallest possible integer value of k (Need help urgently!! Please explain simply because I'm quite slow :/)
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is it 2016*k?
no its like just 2016 x k
that what the * is ...multiplication
sorry I didn't know that LOL
find the prime factorization of 2016
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that would be 2*2*2*2*2*3*7?
you are missing a 3
oh ya sorry 2*2*2*2*2*3*3*7
yes..so you have \[2^5\cdot3^2\cdot7\]
yeap.. then what?
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if all of the exponents were even then you would have a perfect square
oh okay ...
Thanks !
no problem
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