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Mathematics 15 Online
OpenStudy (anonymous):

given that 2016k is a perfect square, what is the smallest possible integer value of k (Need help urgently!! Please explain simply because I'm quite slow :/)

OpenStudy (zarkon):

is it 2016*k?

OpenStudy (anonymous):

no its like just 2016 x k

OpenStudy (zarkon):

that what the * is ...multiplication

OpenStudy (anonymous):

sorry I didn't know that LOL

OpenStudy (zarkon):

find the prime factorization of 2016

OpenStudy (anonymous):

that would be 2*2*2*2*2*3*7?

OpenStudy (zarkon):

you are missing a 3

OpenStudy (anonymous):

oh ya sorry 2*2*2*2*2*3*3*7

OpenStudy (zarkon):

yes..so you have \[2^5\cdot3^2\cdot7\]

OpenStudy (anonymous):

yeap.. then what?

OpenStudy (zarkon):

if all of the exponents were even then you would have a perfect square

OpenStudy (anonymous):

oh okay ...

OpenStudy (anonymous):

Thanks !

OpenStudy (zarkon):

no problem

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