Question

f(theta)=sin(theta)...solve f(theta/2)....theta =60 degrees

Answer 1

\(f(\theta) = \sin(\theta)\)

\(f \left(\dfrac{\theta}{2}\right) = \sin \left(\dfrac{\theta}{2} \right)\)

\(\theta = 60\)

\(f \left(\dfrac{60}{2}\right) = \sin \left(\dfrac{60}{2} \right)\)

\(f(30) = \sin(30)\)

\(f(30) = \dfrac{1}{2}\)