Question

Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

Answer 1

4x - 3y = -12
4x+12=3y
i.e. y= 4/3x+4, comparing it with y=mx+c we find: slope m= 4/3
Parallel lines have same slopes
Therefore, slope of required line m= 4/3
since line passes through point (-3, 4)
Equation of line in slope point form is given as
y-y1=m(x-x1)
y-4=4/3(x-(-3))
3(y-4)=4(x+3))
3y-12=4x+12
3y=4x+24
4x-3y+24=0 is the required equation of the line
@greenlegodude57