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OpenStudy (jennychan12):
Integral of (−9sin(t)sec^2(cos(t))dt ?
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hartnn (hartnn):
put u= cos t du =... ?
OpenStudy (jennychan12):
du = -sintdt
hartnn (hartnn):
good, so your integral, 9 sec^2 (cos t) (-sin t dt) becomes, integral 9 sec^2u du right ?
OpenStudy (jennychan12):
oh, i see now. thanks :)
hartnn (hartnn):
cool, welcome ^_^
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