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Calculus1 6 Online
OpenStudy (jennychan12):

Integral of (−9sin(t)sec^2(cos(t))dt ?

hartnn (hartnn):

put u= cos t du =... ?

OpenStudy (jennychan12):

du = -sintdt

hartnn (hartnn):

good, so your integral, 9 sec^2 (cos t) (-sin t dt) becomes, integral 9 sec^2u du right ?

OpenStudy (jennychan12):

oh, i see now. thanks :)

hartnn (hartnn):

cool, welcome ^_^

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