Question

Integration
int x/(2x+1)dx

Answer 1

u = 2x + 1 ----> x = (u-1)/2
du = 2 dx
dx = 1/2 du
see the integral becomes :
1/2 int (u-1)/(2u) du
= 1/4 int (u-1)/u du
= 1/4 int (1 - 1/u) du
conitinue it .....

Answer 2

that should be easier now

Answer 3

Thank you

Answer 4

wlcm