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solve the system by substitution
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\[\left\{- 4.5x-2y=-12.5 \right\} \left\{ 3.25-y=0.75 \right\}\]
make y by itself in the second equation then plug it in into the first one
Hi, r u sure about this one 3.25 - y = 0.75 ? i mean doesn't it have a "x" term ?
oh yea its \[\left\{ -4.5x-2y=-12.5 \right\} \left\{ 3.25x-y=0.75 \right\}\]
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so... let's name -4.5x - 2y = -12.5 -----(1) 3.25x -y = 0.75 -----(2) now multiply (1) by 10... Wt will u get ?
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