Question

Algebra II help please? Only one question

Answer 1

My birthday is 3/5/1997 so it would be [radical]x-97+3=5

Answer 2

\[\sqrt{x-97}+3=5\]
-3 -3
\[\sqrt{x-97}=2\]
\[\sqrt{x-97}^{2}=2^{2}\]
x-97=4
+97 +97
x=101

Answer 3

to check if it is extraneous plug in x into the original equation and if it comes out to be 5, x isn't an extraneous solution, if it doesn't equal 5 then x=101 is an extraneous solution

Answer 4

Thank you sooo much, I really appreciate it!