“One dollar and eighty-seven cents. That was all. And sixty cents of it was in pennies.”

Let q be the number of quarters, d be the number of dimes, and n be the number of nickels.

25q + 10d + 5n + 60 = 187
q + d + n + 60 = 187
25q + 10d + 5n + 60 = 1.87
25q + 10d + 5n + 60 = 187

Question

“One dollar and eighty-seven cents. That was all. And sixty cents of it was in pennies.”



Let q be the number of quarters, d be the number of dimes, and n be the number of nickels.

25q + 10d + 5n + 60 = 187
q + d + n + 60 = 187
25q + 10d + 5n + 60 = 1.87
25q + 10d + 5n + 60 = 187

anonymous · Answer

if u can help me with this i will become your fan lol

anonymous · Answer

you've typed the 1st & last equations identically. is that right?

anonymous · Answer

25q+10d+5n+60=187 is correct

anonymous · Answer

idk that just the order the answer chooses are in

anonymous · Answer

really

anonymous · Answer

The problem multiplied by 100 to remove the decimals.

anonymous · Answer

ok thanks