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y varies inversely with twice the value of x. When y = 10, x = 3. Find y when x = 5
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"y varies inversely with twice the value of x." \[y=k\frac{ 1 }{ 2x }\]
When y = 10, x = 3. \[(10)=k\frac{ 1 }{ 2(3) }\]\[10=k\frac{ 1 }{ 6 }\]both sides times 6:\[60=k\]
10=k(1/6) 60=K Y=60(1/5) Y=12
thanks up so much dss
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