Question

y varies jointly with x and the square of n. When y = 25, x = 3 and n = 4. Find the value of y when x = 5 and n = 10. Round to the nearest whole number

Answer 1

help me

Answer 2

so the equation is y=xn^2k
so you replace the variables into the equation in order to find k
25=3(4)^2k
25=3(16)k
25=48k
k=25/48 lets just keep this for when we plug it in since its a large decimal
so the equation now is y=25/48xn^2
y=25/48(5)(10^2)
y=25/48(5)(100)
y=25/48(500)
y=260 when rounded to the nearest whole number