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Multiply and reduce (6a^2/5b^2)x(45b^3/18a^3)
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Do u know Indices?
nope
Do u know Division?
yes
we have : 6a^2/5b^2*45b^3/18a^3 Get factor : 3(a^2)/5(b^2)*5(9b^3)/3(6a^3) K ?
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then have : a^2/b^2*9b^3/6a^3 then : 1/1*9b/6a 9b/6a
and can say : 3b/2a
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