Question

Factor completely: 8x^2+20x-12

Answer 1

(8x-4)(x+3) :)

Answer 2

thanks. can you factorise
2t^2-18-20

Answer 3

(2t-20)(t+1)

Answer 4

thank you soooo much. can you possibly factorise
8t^2+20x-12
;)

Answer 5

\[\frac{ x ^{2}+5x+4 }{ x ^{2}+x-12 }\]

Answer 6

Divide all by 4.
2x^2+5x-3
=(2x-1)(x+3)

Answer 7

\[\frac{ \left( x+1 \right) \left( x+4 \right)}{\left( x-3 \right)\left( x+4 \right)}\]

\[= \frac{ \left( x+1 \right)}{ \left( x-3 \right) }\]