Question

log(2x^2+3x)=log(10x+30)

Answer 1

first, take the equation :
2x^2 + 3x = 10x+30
2x^2 + 3x - 10x - 30 = 0
2x^2 - 7x - 30 = 0
solve for x

Answer 2

If \( \log a = \log b\), then \(a = b\).
That is what allows you to set \(2x^2 + 3x\) equal to \(10x + 30\).
Now you have a quadratic in x.
Move all terms to the left side and set equal to zero and solve the quadratic.