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Please help! Find the exact value for cos 165° using the half-angle identity. I have gotten to cos82.5°=+-sqrt(1-.96)/2 The answer I got was cos82.5°=.366 Can someone double check my work?
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cos 165 = -cos 15 = -cos (30/2) = -sqrt [(1+cos30)/2] = -sqrt [(1+sqrt(3)/2)/2] = -sqrt [2+sqrt(3)]/2 Do you see how I did it?
\[-\sqrt{2+\sqrt{3}}/2\]
/2 is outside the sqrt
-.97 is the answer based on my work/solution!
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