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Algebra 19 Online
OpenStudy (anonymous):

The sum of three consecutive integers is 429. Find the numbers. im confused do i just add one to each number or do i add numbers the equal 429?

OpenStudy (ranga):

Assume the first number is N. Then the next two consecutive numbers are (N+1) and (N+2). The sum of the three consecutive numbers = 429. Therefore, N + (N+1) + (N+2) = 429. Solve for N.

OpenStudy (anonymous):

thank you

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