Question

Find the dimensions of the rectangle if the width is 3 feet less than the length and the area is 40ft^2

Answer 1

\(\bf 40 = length \times (length - 3)\)

solve for "length"

Answer 2

(40) x (-3)?

Answer 3

He is asking you to solve 40=l(l-3) for l

You should recognize this is a quadratic equation.

Try multiply l and (l-3) first

I replace the length with l.

Answer 4

Thats a one?

Answer 5

A lowercase L.
1<--this is a one.

Answer 6

40=L(L-3) You like L better?

Either way, this is still a quadratic.
Your objective is
put into this form 0=ax^2+bx+c .

Answer 7

or since we are using L instead of x
into this form 0=aL^2+bL+c