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\[\angle(ABD) = \angle(DBC) = \frac{ 1 }{2 } of \angle(ABC) \]
\[2x+22 = \angle(DBC) = \frac{ 1 }{ 2 } of (8x)\]
ABD = (1/2)ABC or 2ABD = ABC
cuz ur question requires bisecting BD bisects ABC
u can also do it this way, it's a lot easier 2ABD = ABC 2(2x+22) = 8x
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ok
not quite sure on what your questions is trying to find
square is a subset of quadrilateral? or if the quadrilateral has the same size, all the sides were to be equal i'm sorry ,i didn't get ur question xD, but here's a good educated guess
if the quadrilateral has the same size of the square*
no problem, did my best
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