Question

solve

Answer 1

\[\frac{ 2 }{ x}+\frac{ 5 }{ x-2 }=\frac{ 2 }{ x-1 }\]

Answer 2

\[\frac{ \left( 2 \right)\left( x-2 \right) }{ x } + \frac{ 5\left( x \right) }{ x-2 } =\frac{ 2 }{ x-1 }\]

\[\frac{ 2x-4+5x }{ x(x-2) }=\frac{ 2 }{ x-1 }\]

Then cross over and solve the equation.

\[\left( 7x-4)(x-1 \right)=(2(x^{2}-2x)\]

Continue solving:)

Answer 3

5x^2-15x+4=0

Answer 4

do i leave it like this?

Answer 5

no, you have to solve for x

Answer 6

ok