Mathematics
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OpenStudy (anonymous):
3/5a^4(20a^6-10a^3-5/7) Someone help please
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OpenStudy (mertsj):
\[\frac{3}{5}a^4(20a^6-10a^3-\frac{5}{7})\]
OpenStudy (mertsj):
Is that the problem?
OpenStudy (anonymous):
yes
OpenStudy (mertsj):
Use the distributive property
OpenStudy (mertsj):
First multiply:
\[\frac{3}{5}a^4\times 20a^6\]
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OpenStudy (mertsj):
What do you get for that?
OpenStudy (anonymous):
12a^10
OpenStudy (mertsj):
Very good.
OpenStudy (mertsj):
Now do:
\[\frac{3}{5}a^4 \times -10a^3\]
OpenStudy (anonymous):
-6a^7
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OpenStudy (mertsj):
And finally:
\[\frac{3}{5}a^6 \times - \frac{5}{7}\]
OpenStudy (anonymous):
-15/35a^4
OpenStudy (mertsj):
Cancel the 5's before you multiply
OpenStudy (anonymous):
3/7a^4
OpenStudy (mertsj):
Make it negative
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OpenStudy (mertsj):
Now write your answer:
OpenStudy (anonymous):
\[12a ^{10}-6a ^{7}-\frac{ 3 }{ 7 }a ^{4}\]
OpenStudy (mertsj):
\[12a ^{10} - 6a^7-\frac{3}{7}a^4\]
OpenStudy (mertsj):
Perfect.
OpenStudy (anonymous):
can you help me with another
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OpenStudy (mertsj):
Possibly
OpenStudy (anonymous):
(7a+1)(9a+3)
OpenStudy (anonymous):
its factoring
OpenStudy (anonymous):
I got 63a^2+30+3
OpenStudy (anonymous):
what did i do wrong?
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OpenStudy (mertsj):
The middle term should be 21a + 9a which is 30a
OpenStudy (mertsj):
But you said it is factoring and you multiplied the two factors together so what do the directions say to do?
OpenStudy (anonymous):
I need to Foil
OpenStudy (anonymous):
i meant foiling not factoring
OpenStudy (mertsj):
ok. So it should be 63a^2 + 30a +3
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OpenStudy (anonymous):
i was close enough
OpenStudy (mertsj):
Except what you had was really 63a^2+33
OpenStudy (anonymous):
(8x-7)(x+5) is the answer 8x^2+33x-35