Question

simplify 2y^2 x 2y^2 vx^-3 x 9x^9

Answer 1

\[2y^22y^2vx^-3(9x^9)?\]

Answer 2

x^-3

Answer 3

no

Answer 4

What is your question look like then?

Answer 5

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Answer 6

simplify 2y^2 x 2y^2v^-2 vx^-3 x 9x^9
\[2y^2 \times 2y^2v^{-2} vx^{-3} \times 9x^9 \]

Answer 7

so first sort into like terms
2y^2 x 2y^2 x 9x^9 x x^-3 x v x v^-2
\[2y^2 \times 2y^2 \times 9x^9 \times x^{-3} \times v \times v^{-2}\]
next multiply out the integers
\[2 \times 2 \times 9 = 36\]
next add the powers of like terms
\[y^2 \times y^2 = y^{2+2} = y^4\]
\[x^9 \times x^{-3} = x^{9+(-3)} = x^6\]
\[v \times v^{-2} = v^{1+(-2)} = v^{-1}\]
now combine
\[2y^2 \times 2y^2 \times 9x^9 \times x^{-3} \times v \times v^{-2} = 36 \times y^4 \times x^6 \times v^{-1}\]
\[= 36y^4 x^6 v^{-1} = \frac{36y^4 x^6} {v}\]