Question

An arrow hits the target at 17.0m/s and penetrates for 0.0085s at an acceleration of -1550m/s^2. The target's magnitude has an acceleration of 450 m/s^2 How far does the arrow penetrate?

Answer 1

we use
v^2=u^2+2as
where v=final velocity =0;
initial velocity =17m/s
and a=-1550m/s^2
then u^2=2as
and s= distance=u^2/2a
s=.093m