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hartnn (hartnn):
any particular question ?
OpenStudy (anonymous):
the amount of perol p liters that a car consumes varies directly as the distance d km traveled.if a car can travel 100 km on 8 liters,how far can it go with 30 liters of petrol?
hartnn (hartnn):
x directly varies y means \(\Large x=ky\)
hartnn (hartnn):
so, here we have ,
\(\Large p=kd\)
where k is the constant of variation, got this /?
hartnn (hartnn):
.if a car can travel 100 km on 8 liters <----means p=8 , d=100
can you first find k from this info ?
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hartnn (hartnn):
no ?
8 = 100 k
k= ... ?
OpenStudy (anonymous):
how to start the answer
hartnn (hartnn):
like this,
for direct variation,
p=kd
when p=8, d=100
so,
8=k*100
so, k=...
can u continue ?
OpenStudy (anonymous):
not really
OpenStudy (anonymous):
\[8*10\]
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hartnn (hartnn):
8 =k*100
k = 8/100 = 2/25
hartnn (hartnn):
so, we have p=(2/25)d
now put here p=30 and try to find d
OpenStudy (anonymous):
how does it comes 2/25
hartnn (hartnn):
8 = 4*2
and 100 = 4*25
hartnn (hartnn):
the 4's get cancelled
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OpenStudy (anonymous):
now need to find d
OpenStudy (anonymous):
any idea to find d
hartnn (hartnn):
why don't u try first ?
hartnn (hartnn):
p=(2/25)d
now put here p=30 and try to find d
OpenStudy (anonymous):
30*8
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hartnn (hartnn):
i will suggest you to practice alot! you lack basic algebraic simplification ability...
hartnn (hartnn):
p=(2/25)d
30=(2/25)d
d = 30 *25/2 = ...
OpenStudy (anonymous):
375
hartnn (hartnn):
yup, d= 375
OpenStudy (anonymous):
thx alot
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