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Inverse trigonometric functions, Can you please help me solve this exersise ? http://screencast.com/t/j98tQ6lhv2Z1
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\(\sin \theta = -\dfrac{3}{4} \)
\( \sec \theta = \dfrac{1}{\cos \theta} \)
For the angle \(\theta \) in the figure, what is \( \cos \theta \) ?
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3/4 ?
oh wait in the figure
yes
- 3/ 4
I found 4/sqrt(7) for a
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You need to find the other leg of the triangle.The cos function is the adjacent leg over the hypotenuse.
is it correct ??
I stole a formula from the internet
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