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Precalculus
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what is the standard form of the equation of the circle with center (3,-2) and a point on the circle (-1,1)
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can u find the distance between those 2 points ? that would be the radius r
using the distance formula
yes
i got 13
how?
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3--1 = 4 , 4^2=16 -2-1=-3, -3^2-9
-3^2=9***
i didnt square the 4
so its 25
sqrt 25 =...?
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5
you have centre , u have radius r=5, can you find the equation now?
is it (x+1)^2+(y-1)^2=5
the center is 3,-2 not -1,1
\((x-h)^2+(y-k)^2=r^2\)
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h=3,k=-2
so its (x-3)^2 and (y+2)^2= 25
yes + instead of and
thanks
welcome ^_^
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