Question

f(x)=2x^2-x-1
if f(x)=-1, what is x? What point(s) are on the graph of f?

Answer 1

its easy . f(x)=2x^2-x-1

now f(x)=-1

by plugging values we get

-1=2x^2-x-1

which is equal to

0=2x^2-x

take x as common

we get 0=x(2x-1)

so x=0 or x=1/2

now we can find points