Question

Please Help ! The population of Parellel double every 30 years. Its current population is 50,000.

Write a mathematical model for the population as a function of time from now, measured in 30-year periods

Answer 1

Population = 50,000 *(2^(y/30))
So after 30 years, population = 50,000 *2^(30/30) =
50,000 * 2^1 = 100,000

Answer 2

thanks how can I rewrite it so that time is measured in years ?

Answer 3

Time is measured in years.
example after 15 years population equals
50,000 *(2^(y/30)) =
50,000 *(2^(15/30)) =
50,000 *(2^(.5)) =
50,000 *(1.4142135624)
=70,711.

Answer 4

Yeah but the first equation is measured in the 30 year increments. Would the equation be the same if you wanted to plug in any years in it ? without the 30 years ?

Answer 5

50,000 *(2^(y/30))
In the formula the y stands for years and you can input any time amount into it.
Want to calculate population afetr 3 months?
50,000 *(2^(y/30))
y=.25 and so
50,000 *(2^(.25/30)) =
Population = 50,000 *(2^(1/120))
Population = 50,000 * (2^0.0083333333)
Population = 50,000 * (2^0.0083333333)
Population = 50,000 * 1.0057929411
Population = 50,290

Answer 6

Okay thank you so much!!!

Answer 7

u r welcome