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find the tangents of the curve xy=18 from (4,4) please help. the answers are x+ 2y = 12 and 2x + y = 12
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what is the dy/dx of the equation
make y the subject then differentiate
so dy/dx = x??
nope \[y = \frac{18}{x}\]which in index form is \[y = 18x^{-1}\] now you can find the derivative
dy/dx = 18? aaah not sure..
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nope \[y' = - \frac{18}{x^2}\]
the point (4, 4) isn't on the curve...
okay okay thanks!!!!
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