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4/(-2-2i)
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\[\frac{ 4 }{ -2-2i} \times \frac{ -2 +2i }{ -2 +2i }\]
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= \[\frac{ -8 +8i }{-8}\]
I mean positive 8
Bottom should be +8
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lol yes that
Then reduce the fraction.
-1 + i
Is that correct?
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