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Calculus1
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Parametric curve x(t)=sin(3pit), y(t)=cos(2pit). t is between [0,2]. Find axis intercepts & turning points
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ok, lets find the intercepts x-intercept: where y is zero, it will cut the x y-intercept: where x is zero, it will cut the y
i got that far and wrote that for x it equals sin(0) & sin(6pi) and both = 0
therefore (x,y)= (0,0) & (0,2)
what makes this difficult is we are in 3D, I didn't even notice: |dw:1381134432309:dw|
is it we haven't learnt about 3d yet it is just X & y axis
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it's a parametric curve
but we have x, y and t ??
usually - we have just y(x) = ...
ok,I guess i go wrong approach
I don't know how to do this...
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|dw:1381134784361:dw| what is t ???
t in between [0,2]
|dw:1381134833002:dw|
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