Question

I need help on the first one, and I need someone to check the two I did on my own:
1. Given the equation -4squrt(x-3)=12, solve for x and identify if it is an extraneous solution.
x = 0, solution is not extraneous

x = 0, solution is extraneous

x = 12, solution is not extraneous

x = 12, solution is extraneous

Answer 1

don't even start

Answer 2

2. Given the equation
\[\sqrt{8X+1}=5\]
x = One fourth, solution is not extraneous

x = One fourth, solution is extraneous

x = 3, solution is not extraneous

x = 3, solution is extraneous (my ans x = One fourth, solution is not extraneous

x = One fourth, solution is extraneous

x = 3, solution is not extraneous

x = 3, solution is extraneous
were)

Answer 3

\[-4\sqrt{x-3}=12\] has no solution because the left hand side is negative and the right hand side is positive

Answer 4

Oh so it would be x = 0, solution is not extraneous

Answer 5

no, it would be no solution because the left hand side is negative and the right hand side is positive

Answer 6

The second on I did, I got x = 3, solution is extraneous
I just want to know if I'm right

Answer 7

Oh...no solution isn't a option

Answer 8

and I need to see if im right about the one above and this one:
\[\sqrt{x+9}-4=1\]
x = 16, solution is not extraneous

x = 16, solution is extraneous (MY ANSWERE)

x = 34, solution is not extraneous

x = 34, solution is extraneous

Answer 9

2. Given the equation
\[\sqrt{8X+1}=5\]

x = One fourth, solution is not extraneous

x = One fourth, solution is extraneous

x = 3, solution is not extraneous

x = 3, solution is extraneous (my answer)