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Algebra 13 Online
OpenStudy (anonymous):

4y-1/1-16y^2

OpenStudy (anonymous):

The denominator of that fraction is a difference of squares...you need to factor it accordingly and something will cancel.

OpenStudy (anonymous):

−16y2+4y−1

OpenStudy (anonymous):

No. This is a fraction. This question is not testing her knowledge that 1/1 = 1

OpenStudy (anonymous):

oh

OpenStudy (anonymous):

4y-1/1-16y^2=4y+1 Is it correct ?

OpenStudy (anonymous):

yes

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