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Precalculus
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solve algebraically x-y+z=5 -2x-y-z=-6 3x+3y-2z=-5 a. (1,0,4) b. (0,-1,6) c. (-1,-2,4) d.(-3,0,2)
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It's a) just substitute one in for the other I did x = 5 +y-z and put it into the second one, then went from there :)
thankyou
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