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OpenStudy (anonymous):
please help ill buy you a cookie Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution. x = 0, solution is not extraneous x = 0, solution is extraneous x = 12, solution is not extraneous x = 12, solution is extraneous
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OpenStudy (loser66):
I want 3 cookies, OK?
OpenStudy (anonymous):
ok :D
OpenStudy (anonymous):
do you know how to set it up to solve the equation for x?
OpenStudy (loser66):
|dw:1381182725846:dw|
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