Question

Tan(INVsin3/4- INVcos1/5)

Answer 1

\(\bf tan\left[\cfrac{sin^{-1}\left(\frac{3}{4}\right)}{cos^{-1}\left(\frac{1}{5}\right)}\right] \quad ? \)

Answer 2

It's tan(sin-cos)

Answer 3

ohh yea.. so \(\bf tan\left[sin^{-1}\left(\frac{3}{4}\right)-cos^{-1}\left(\frac{1}{5}\right)\right]\)

Answer 4

keep in mind that the inverse trig functions, for sine, will have a range between \(\bf \cfrac{\pi}{2}\textit{and }-\cfrac{\pi}{2}\) and the inverse function for cosine has a range of \(\bf 0 \ to \pi\)

Answer 5

after drawing the triangles and plugging it to the formula
is this correct?